Test booklet: प्रश्न पुस्तिका
Booklet No.: 1209331
Series: C

IBPS PO Prelims Paper 2

Questions: 100
Maximum marks: 100
Minutes allowed: 60

Instructions निर्देश

This booklet has 100 questions in 3 parts: A. English Language (30), B. Quantitative Aptitude (35), C. Reasoning Ability (35).
Each part has its own clock. When it runs out, that part closes and the next opens.
Each question has 5 options and one right answer. Marks per question are shown with each part. Negative marking differs by part, as in the notice. A question left blank scores nothing.
Fill one bubble per question on the answer sheet. Unlike a real sheet, you can clear it and change your mind.

Scripting is off, so this page is a printed paper: answer on paper, then open each question’s working.

Part BQuantitative Aptitude

35 questions, 0.86 marks each, 0.21 off for a wrong answer

342 is what percent of 760?

Question 31 40% 90% 45% 50% 55%

Answer and working
Answer C
342 ÷ 760 × 100 = 45%.
A boat covers 36 km downstream in 3 hours and 40 km upstream in 4 hours. What is the speed of the stream?

Question 32 2 km/h 3 km/h 1 km/h 11 km/h 4 km/h

Answer and working
Answer C
Downstream speed = 36 ÷ 3 = 12 km/h; upstream = 40 ÷ 4 = 10 km/h. Stream = (12 − 10) ÷ 2 = 1 km/h.
Solve both equations and compare x and y.
I. x² − 3x − 10 = 0
II. y² − 4y − 96 = 0

Question 33 x > y x ≥ y x < y x ≤ y x = y or no relation can be established

Answer and working
Answer E
I gives x = −2 or 5. II gives y = −8 or 12. Some x are bigger and some smaller than some y, so no single relation holds: x = y or no relation can be established.
A trader buys a bicycle for ₹1,850 and sells it for ₹1,554. What is the profit or loss percent?

Question 34 14% loss 19.05% loss 16% loss 21% loss 16% profit

Answer and working
Answer C
Loss = ₹296. As a percent of the cost price: 296 ÷ 1,850 × 100 = 16% loss.
Find the wrong number in the series: 4, 8, 17, 33, 54, 94, 143

Question 35 17 143 33 4 54

Answer and working
Answer E
The rule: the differences are squares: 4, 9, 16, 25, 36, 49. The term in place of 54 should be 58, so the wrong number is 54.
Find the wrong number in the series: 19, 25, 34, 46, 64, 79, 100

Question 36 46 25 64 79 19

Answer and working
Answer C
The rule: the differences grow by 3: 6, 9, 12, 15, 18, 21. The term in place of 64 should be 61, so the wrong number is 64.
Solve both equations and compare x and y.
I. x² − 12x = 0
II. y² + y − 30 = 0

Question 37 x > y x ≥ y x < y x ≤ y x = y or no relation can be established

Answer and working
Answer E
I gives x = 0 or 12. II gives y = −6 or 5. Some x are bigger and some smaller than some y, so no single relation holds: x = y or no relation can be established.
A and B together can do a job in 30 days. A alone can do it in 50 days. In how many days can B alone do it?

Question 38 80 days 60 days 75 days 25 days 105 days

Answer and working
Answer C
B’s one day = 1/30 − 1/50 = 1/75. B alone takes 75 days.
Solve both equations and compare x and y.
I. x² − 10x = 0
II. y² + 2y − 3 = 0

Question 39 x > y x ≥ y x < y x ≤ y x = y or no relation can be established

Answer and working
Answer E
I gives x = 0 or 10. II gives y = −3 or 1. Some x are bigger and some smaller than some y, so no single relation holds: x = y or no relation can be established.
Which number replaces the question mark? 4, 5, 12, 39, 160, ?

Question 40 805 1,450 806 804 281

Answer and working
Answer A
The rule: each term is the previous × 1 + 1, × 2 + 2, × 3 + 3, and so on. The missing term is 805.
By selling a watch for ₹456, a man loses 5%. For how much should he sell it to gain 20%?

Question 41 ₹570 ₹576 ₹500 ₹596 ₹547

Answer and working
Answer B
CP = 456 × 100/95 = ₹480. For a 20% gain: 480 × 120/100 = ₹576.
Solve both equations and compare x and y.
I. x² − 2x − 24 = 0
II. y² − 6y − 27 = 0

Question 42 x > y x ≥ y x < y x ≤ y x = y or no relation can be established

Answer and working
Answer E
I gives x = −4 or 6. II gives y = −3 or 9. Some x are bigger and some smaller than some y, so no single relation holds: x = y or no relation can be established.
A train 210 m long crosses a platform 600 m long in 81 seconds. What is the speed of the train?

Question 43 18 km/h 36 km/h 54 km/h 27 km/h 10 km/h

Answer and working
Answer B
It must cover its own length and the platform: 210 + 600 = 810 m in 81 s, so 10 m/s = 10 × 18/5 = 36 km/h.
A train 270 m long crosses a platform 300 m long in 38 seconds. What is the speed of the train?

Question 44 63 km/h 72 km/h 45 km/h 54 km/h 15 km/h

Answer and working
Answer D
It must cover its own length and the platform: 270 + 300 = 570 m in 38 s, so 15 m/s = 15 × 18/5 = 54 km/h.
The present ages of Asha and her father are in the ratio 1 : 5. After 7 years, the ratio will be 3 : 8. What is Asha’s present age?

Question 45 7 years 5 years 15 years 12 years 25 years

Answer and working
Answer B
Ages 1x and 5x. (1x + 7) : (5x + 7) = 3 : 8 gives x = 5. Asha is 1 × 5 = 5 years.
Simplify: ²⁄₃ + ⁹⁄₁₀ + ²⁄₃

Question 46 ⁶⁷⁄₃₀ ⁶⁷⁄₃₁ ¹¹⁄₅ ³⁴⁄₁₅ ¹⁹⁄₂₅

Answer and working
Answer A
Over the common denominator 60: the sum is ⁶⁷⁄₃₀. Adding tops and bottoms separately (19/25) is the trap.
Directions for questions 47 to 51
Study the table and answer the questions that follow.
Students enrolled in five coaching centres, in two successive years
Centre Year 1 Year 2
Centre A 800 1,040
Centre B 800 880
Centre C 400 520
Centre D 460 529
Centre E 640 768
By what percent did Centre E’s figure change from Year 1 to Year 2?

Question 47 20% decrease 16.67% increase 25% increase 20% increase 15% increase

Answer and working
Answer D
Change = 768 − 640 = 128. On Year 1: 128 ÷ 640 × 100 = 20% increase.
What is the total for Centre D over the two years?

Question 48 1,058 1,009 989 980 969

Answer and working
Answer C
460 + 529 = 989.
What is the average Year 2 figure of the five?

Question 49 737.4 747.4 620 683.7 757.4

Answer and working
Answer B
Sum of Year 2 = 3,737. ÷ 5 = 747.4.
What is the ratio of Centre D’s Year 1 figure to Centre C’s Year 2 figure?

Question 50 26 : 23 529 : 400 23 : 20 529 : 520 23 : 26

Answer and working
Answer E
460 : 520 = 23 : 26.
Centre D’s Year 2 figure is what percent of Centre B’s Year 2 figure?

Question 51 57.5% 50.11% 60.11% 70.11% 166.35%

Answer and working
Answer C
529 ÷ 880 × 100 = 60.11%.
What is the value of 74² − 35²?

Question 52 1,521 4,351 11,663 4,181 4,251

Answer and working
Answer E
a² − b² = (a + b)(a − b) = 109 × 39 = 4,251.
A sum of money doubles itself in 20 years at simple interest. What is the rate of interest per annum?

Question 53 10% 5% 4.55% 2.5% 7.5%

Answer and working
Answer B
The interest earned is 1 times the principal in 20 years. Rate = 1 × 100 / 20 = 5%.
What is the fourth proportional to 13, 6 and 130?

Question 54 73 54 66 123 60

Answer and working
Answer E
13 : 6 = 130 : x, so x = 6 × 130 ÷ 13 = 60.
Simplify: ⁵⁄₆ + ¹⁄₈ + ¹⁄₂

Question 55 ¹⁷⁄₁₂ ⁷⁄₁₃ ⁷⁄₅ ³⁵⁄₂₄ ³⁄₂

Answer and working
Answer D
Over the common denominator 24: the sum is ³⁵⁄₂₄. Adding tops and bottoms separately (14/26) is the trap.
What is the compound interest on ₹41,200 for 2 years at 10% per annum, compounded annually?

Question 56 ₹49,852 ₹8,652 ₹4,120 ₹12,772 ₹8,240

Answer and working
Answer B
Amount = 41,200 × (1 + 10/100)² = ₹49,852. CI = 49,852 − 41,200 = ₹8,652.
Find the wrong number in the series: 30, 36, 46, 62, 78, 100, 126

Question 57 100 62 36 46 126

Answer and working
Answer B
The rule: the differences grow by 4: 6, 10, 14, 18, 22, 26. The term in place of 62 should be 60, so the wrong number is 62.
70 litres of a mixture contains milk and water in the ratio 3 : 4. How much water must be added to make the ratio 1 : 4?

Question 58 84 litres 40 litres 80 litres 16 litres 120 litres

Answer and working
Answer C
Milk = 30 l, water = 40 l. For 1 : 4, water must be 30 × 4/1 = 120 l. Add 120 − 40 = 80 litres.
Simplify: 46 + 13 × 11 − 36 ÷ 3

Question 59 637 177 180 201 204

Answer and working
Answer B
Division and multiplication first: 13 × 11 = 143 and 36 ÷ 3 = 12. Then 46 + 143 − 12 = 177.
Simplify: ¹⁄₂ + ¹⁄₈ + ⁹⁄₁₀

Question 60 ³¹⁄₂₀ ³⁄₂ ¹¹⁄₂₀ ⁶¹⁄₄₀ ⁶¹⁄₄₁

Answer and working
Answer D
Over the common denominator 40: the sum is ⁶¹⁄₄₀. Adding tops and bottoms separately (11/20) is the trap.
The population of a town is 22,900. It grows by 10% every year. What will it be after 2 years?

Question 61 27,709 25,190 27,016 29,095 27,480

Answer and working
Answer A
22,900 × (1 + 10/100)² = 22,900 × 1.21 = 27,709. Growing 10% on 22,900 twice, not 20% once.
Two fair dice are thrown together. What is the probability that the sum is 4?

Question 62 ¹⁄₄ ¹⁄₁₂ ¹⁄₂ ¹¹⁄₁₂ ¹⁄₉

Answer and working
Answer B
There are 36 equally likely outcomes and 3 of them qualify. Probability = ¹⁄₁₂.
Solve both equations and compare x and y.
I. x² + 2x − 3 = 0
II. y² − 5y − 14 = 0

Question 63 x > y x ≥ y x < y x ≤ y x = y or no relation can be established

Answer and working
Answer E
I gives x = −3 or 1. II gives y = −2 or 7. Some x are bigger and some smaller than some y, so no single relation holds: x = y or no relation can be established.
The average weight of 10 people goes up by 4 kg when a new person takes the place of one who weighs 50 kg. What does the new person weigh?

Question 64 90 kg 86 kg 94 kg 10 kg 54 kg

Answer and working
Answer A
The total rises by 10 × 4 = 40 kg, so the new person weighs 50 + 40 = 90 kg.
Which number replaces the question mark? 5, 7, 11, 13, 17, 19, ?

Question 65 24 22 23 21 27

Answer and working
Answer C
The rule: consecutive prime numbers. The missing term is 23.

IBPS PO Prelims Paper 2

Instructions निर्देश

Part AEnglish Language

Part BQuantitative Aptitude

Part CReasoning Ability

Centre	Year 1	Year 2
Centre A	800	1,040
Centre B	800	880
Centre C	400	520
Centre D	460	529
Centre E	640	768